:a 10 g bullet travelling at 300 m/s hits a 500 g wooden block that is initially stationary. the bullet becomes embedded in the block, and both travel together along a frictioneless surface. answer each of the following questions a) what is the kinetic energy of the bullet before it hits the block? b) what is the velocity of the bullet+block after the collision?

450 J

5.88235 m/s

Explanation:

The kinetic energy is given by

The kinetic energy of the bullet before it hits the block is 450 J

= Mass of bullet = 0.01 kg

= Mass of block = 0.5 kg

= Initial Velocity of bullet = 300 m/s

= Initial Velocity of second block = 0 m/s

v = Velocity of combined mass

In this system the linear momentum is conserved

The velocity of the bullet+block after the collision is 5.88235 m/s

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