Apitcher throws a baseball with a velocity of 40 m/s. after being struck by a bat the ball travels in the opposite direction with a velocity of 50 m/s. if the ball has a mass of 0.145 kg and is in contact with the bat for 3.0 ms, the magnitude of the average force exerted by the bat on the ball is

Force on the ball will be 4350 N

Explanation:

We have given that mass of the baseball m = 0.145 kg

Initial velocity of the baseball u = 40 m/sec

And final velocity v = - 50 m/sec ( in opposite direction )

So change in momentum =

Time is given as

We know that change in momentum is given by impulse

So

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray