Your friend decides to generate electrical power by rotating a 100,000 turn coil of wire around an axis in the plane of the coil and through its center. the coil is perpendicular to earth's magnetic field in a region where the field strength is equal to 0.300 g. the loops of the coil have a radius of 28.0 cm, and the coil has negligible resistance.

(a) if your friend turns the coil at a rate of 140 rev/s, what peak current will exist in a 1400 o resistor that is connected across the terminals of the coil?
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(b) the average of the square of the current will equal half of the square of the peak current. what will be the average power delivered to the resistor?

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge