We move a square loop of wire 2.3 cm on a side into a region of uniform magnetic field of 1.5 t with the plane of the loop perpendicular to the direction of the field. the loop is moving with a constant velocity of 2.1 m/s into the field region starting from a point outside the field. if the loop has a resistance of 3 ω, find the force on the loop as it just enters the magnetic field region. (enter the magnitude.)

Force will be

Explanation:

We have given side of wire d = 2.3 cm = 0.023 m

Magnetic field B = 1.5 T

Velocity v = 2.1 m/sec

Resistance R = 3 ohm

We know that current is given by

Power is given by

We know that power is also given by

So

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.