For such a potential, the transmission coefficient does not have the simple form |f| 2/|a| 2 because the potential does not go to zero as x → [infinity]. as a result, the transmitted wave travels at a different speed. show that in this case t = q e−v0 e |f| 2 |a| 2 . do this by noting that t is the probability of finding the wave in x > 0 relative to some incident probability in x < 0. for a plane wave, we can define an incident probability in a finite region – for example, in a particular area over a time interval dt. use this to argue that t = |f| 2 |a| 2 vt vi where vt , vi are the velocities of the transmitted and incident waves, and then use your knowledge of the velocity of a plane wave in terms of its energy.