A0.0625 tank contains 0.0925kg nitrogen at a gauge pressure of 5.17atm. find the temperature of the gas in degree celsius

-271.96 °C

We are given;

we are required to calculate the temperature of the gas.

Moles = Mass ÷ Molar mass

Molar mass of nitrogen gas = 28.0 g/mol

Therefore;

Moles of N₂ = 92.5 g ÷ 28.0 g/mol

                   = 3.304 moles

According to the ideal gas equation;

PV = nRT , where n is the number of moles and R is the ideal gas constant, 0.082057 L.atm/mol.K

Rearranging the formula;

T = PV ÷ nR

  = ( 5.17 atm × 0.0625 L) ÷ (3.304 moles × 0.082057)

  = 1.19 K

But, °C = K - 273.15

Therefore;

T = 1.19 K - 273.15

  = -271.96 °C

Thus, the temperature of the gas will be -271.96 °C