The element niobium, which is a metal, is a superconductor (i. e., no electrical resistance) at temperatures below 9 k. however, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10 t. what is the maximum current in a straight, 3.2-mm-diameter superconducting niobium wire?

I=800A

Explanation:

1) Important concepts

Magnetic field represented by B=0.1T, and is defined as"A field  generated when an electric charge via electrons move through the space or in an electrical conductor."

I represent the current (variable os interest)

r represent the radius= 3.2/2 = 1.6mm = 0.0016m

2) Formula to use

For this case we can use the magnetic field due to a wire with current formula, given by:

is a constant

Solving for I from the last formula we got:

And replacing the values given we have:

So the current passing thorugh the wire would be 800 A.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.