The density of a solid cube is 678.2 kg/m^3. (note that each edge is 4.8 cm in length and the mass is 75g.) when the cube is placed in a container of water, it is observed to float (it reaches equilibrium when part of the cube is below he surface or water.) what is the magnitude of the buoyancy force acting on the cube in n, and what percentage of the cube's volume is underwater while in equilibrium?

Part a)

F = 0.735 N

Part b)

Explanation:

As we know that mass of the cube is given as

Now we know that cube is floating in the water

So net force due to weight of the cube must be counter balanced by buoyancy force on the liquid

so we have

Part b)

Percentage of volume submerged into the liquid is given as

now percentage of submerged liquid is given as

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west