The force required to stretch a hooke’s-law spring varies from 0 n to 43.2 n as we stretch the spring by moving one end 14.4 cm from its unstressed position. find the force constant of the spring. answer in units of n/m.

Spring constant = 300 N/m

Explanation:

For a spring we have force is the product of spring constant and displacement.

          Force = Spring constant x Displacement

          F = k x

Here Force , F = 43.2 - 0 = 43.2 N

         Displacement, x = 14.4 cm = 0.144 m

Substituting

              F = k x

              43.2 = k x 0.144

               k= 300 N/m

Spring constant = 300 N/m

probably not if net force is zero

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day