Abaseball is pitched at 30 m/s and hit by a bat. after leaving the bat, the ball has a velocity of 40 m/s. the ball weighs 0.14 kg. the time elapsed during the collision was 0.0020 seconds. what was the force (f) exerted on the baseball? hint: watch your signs of the velocities, the direction changes.

Force exerted on the ball, F = -4900 N

Explanation:

It is given that,

Mass of the ball, m = 0.14 kg

Initial speed of the ball, u = +30 m/s

Final speed of the ball, v = -40 m/s (opposite direction)

Time taken, t = 0.002 s

Let F is the force exerted on the baseball. We know that the force exerted on an object is equal to the product of mass and acceleration. Using second law of motion, the force is given by :

F = ma

F = -4900 N

So, the force exerted on the baseball is -4900 N and it is exerted in opposite direction. Hence, this is the required solution.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.