Aladder of length l = 2 m and mass m = 18 kg rests on a floor with coefficient of static friction μs = 0.55. assume the wall is frictionless. 1) what is the normal force the floor exerts on the ladder?

To solve this problem we must resort to the definition of Normal Force, in which, it is the component of a contact force that is perpendicular to the surface that an object contacts.

where,

m=mass

g= Gravitational Acceleration

Normal force that the force exerts on the ladder is the weight of the ladder, then

F=mg

F=18*9.8

F=176.58N

Therefore normal force the floor exerts on the ladder is 176.58N

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.