2. suppose that a parallel-plate capacitor has circular plates with radius r = 30 mm and a plate separation of d = 5.0 mm. suppose also that a sinusoidal potential difference with a maximum value and a frequency of =60 hz is applied across the plates. find , the maximum value of the induced magnetic field that occurs at r = r. express your answers in terms of variables first and then plug in numbers afterword.

The maximum value of the induced magnetic field is .

Explanation:

Given that,

Radius of plate = 30 mm

Separation = 5.0 mm

Frequency = 60 Hz

Suppose the maximum potential difference is 100 V and r= 130 mm.

We need to calculate the angular frequency

Using formula of angular frequency

Put the value into the formula

When r>R, the magnetic field is inversely proportional to the r.

We need to calculate the maximum value of the induced magnetic field that occurs at r = R

Using formula of magnetic filed

Where, R = radius of plate

d = plate separation

V = voltage

Put the value into the formula

Hence, The maximum value of the induced magnetic field is .

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the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.