Two air track carts move along an air track towards each other. cart a has a mass of 450 g and moves toward the right with a speed of 0.850 m/s and air track cart b has a mass of 300 g and moves toward the left with a speed of 1.12 m/s. what is the total momentum of the system?
a) 0.719 kg•m/s toward the right
b) 0.719 kg•m/s toward the left
c) 0.750 kg•m/s toward the right
d) 0.047 kg•m/s toward the right
e) 0.750 kg•m/s toward the left

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

Explanation:

Hi there!

The total momentum of the system is given by the sum of the momentum vectors of each cart. The momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

Then, the momentum of the system will be the momentum of cart A plus the momentum of cart B (let´s consider the right as the positive direction):

mA · vA + mB · Vb

0.450 kg · 0.850 m/s + 0.300 kg · (- 1.12 m/s) = 0.047 kg · m/s

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

resonant frequency