How much will the temperature of a 250 g block of silver increase if 2000 cal of heat is added to it?

143.37 K or °C

We are given;

We are required to determine change in temperature for the block of ice.

Q = m × c × ΔT, where M is the mass of an object, c is the specific heat capacity and ΔT is the change in temperature.

In this case;

Q = 2000 calories

Mass = 250 g

specific heat , c of silver is 0.0558 cal/g°C

Therefore;

Rearranging the formula;

ΔT = Q ÷ mc

    = 2000 cal ÷ (250 g × 0.0558 cal/g°C)

    = 143.37 °C or K

The change in temperature is 143.37 K or °C

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explanation: