Suppose a ball of putty moving horizontally with 1kg. m/s of momentum collides and sticks to an identical ball of puffy moving vertically with 1 kg. m/s of momentum. what is the magnitude of their combined momentum? why is their combined momentum not simply the arithmetic sum, 2 kg. m/s?

Vector sum of two vectors at right angles

p={p₁²+p₂²} =2 =1.41 kg•m/s

Explanation:

the journeys of marquette, joliet and la salle a) new france expand.

all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

this was a big portion of territory and expanded new france which before then only consisted of quebec province in northeastern canada

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m