Physics, 19.11.2019 23:31, keshan3000
Acube of ice at an initial temperature of -15.00°c weighing 12.5 g total is placed in 85.0 g of water at an initial temperature of 25.00°c. when thermal equilibrium is achieved, the final temperature is 22.24°c. what is the specific heat capacity of ice?
Answers: 1
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](/tpl/images/0382/0307/09236.png)
......(1)
= mass of ice = 12.5 g
= mass of water = 85.0 g
= final temperature = 22.24°C
= initial temperature of ice = -15.00°C
= initial temperature of water = 25.00°C
= specific heat of ice = ?
= specific heat of water = 4.186 J/g°C![12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]](/tpl/images/0382/0307/da253.png)
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Acube of ice at an initial temperature of -15.00°c weighing 12.5 g total is placed in 85.0 g of wate...
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