Arope applies a horizontal force of 200 n to pull a crate a distance of 4 m across the floor. a frictional force of 90 n opposes this motion. a. what is the work done by the force applied by the rope? b. what is the work done by the frictional force?
c. what is the total work done on the crate?

A. 800 J

B. - 360 J

C. 440 J

Explanation:

Applied force, F = 200 N

Friction force, f = 90 N

Distance, d = 4 m

Work done = Force x distance x cos θ

where, θ be the angle between the force and distance.

A. W = Applied force x distance = 200 x 4 x cos0 = 800 J

B. W = frictional force x distance = 90 x 4 x cos 180 = - 360 J

C. Total work done = 800 - 360 = 440 J