Sphere a is attached to the ceiling of an elevator by a string. a second sphere is attached to the first one by a second string. both strings are of negligible mass. here m1 = m2 = m = 3.14 kg.(a) the elevator starts from rest and accelerates downward with a = 1.35 m/s2. what are the tensions in the two strings in newtons? t1 = nt2 =.(b) if the elevator moves upward instead with the same acceleration what will be the tension in the two strings in newtons? t1 = = .(c) the maximum tension the two strings can withstand is 92.6 n. what maximum upward acceleration (in m/s2) can the elevator have without having one of the strings /s2.

Part a)

Part b)

Part c)

Explanation:

Part a)

As we know that the elevator is accelerating downwards

so we have force equation for sphere A given as

also for second sphere we have

from above equations we have

so we have

Now from other equation we have

Part b)

Now the elevator is accelerating upwards

so we have force equation for sphere A given as

also for second sphere we have

from above equations we have

so we have

Now from other equation we have

Part c)

Now we know that maximum possible tension in the string is

T = 92.6 N

so we have

answer; ///(74) degrees is your answer..

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.