Ahigh-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and diameter 75.0 cm. the power is off for 30.0 s, and during this time the flywheel slows due to friction in its axle bearings. during the time the power is off, the flywheel makes 200 complete revolutions.
(a) at what rate is the flywheel spinning when the power comes back on?
(b) how long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

The final angular speed of the flywheel before the power comes back on is 31.43 rad/s.

The time taken for the flywheel to stop if the power had not come back is 75 s.

The number of revolutions the wheel would have made during this time is 312.5 revolutions.

The given parameters;

The angular acceleration of the wheel is calculated as follows;

(a) The final angular speed of the flywheel is calculated as follows;

(b) The time taken for the flywheel to stop if the power had not come back, is calculated as follows;

The number of revolutions the wheel would have made during this time is calculated as follows;

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Part a)

Part b)

Explanation:

Initial speed of the flywheel is given as

initial angular speed is given as

Number of revolutions

angular displacement is given as

now we have

Part a)

final angular speed of the wheel is given as

Part b)

If the final angular speed becomes zero then time taken by the wheel is given as

Now total number of revolution that it makes is given as

which statement about this sum is true? −245+2.7

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14