You are exploring a distant planet. when your spaceship is in a circular orbit at a distance of 630 km above the planet's surface, the ship's orbital speed is 5500 m/s . by observing the planet, you determine its radius to be 4.48×106 m. you then land on the surface and, at a place where the ground is level, launch a small projectile with initial speed 14.6 m/s at an angle of 30.8∘ above the horizontal. if resistance due to the planet's atmosphere is negligible, what is the horizontal range of the projectile?

Explanation:

As we know that the orbital speed is given as

here we know that

v = 5500 m/s

now we have

now acceleration due to gravity of planet is given as

now range of the projectile on the surface of planet is given as

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

its c i just checked it