Car a rear ends car b, which has twice the mass of a, on an icy road at a speed low enough so that the collision is essentially elastic. car b is stopped at a light when it is struck. car a has mass m and speed v before the collision. find the speed of car b after the collision (in terms of v).

Vb = v/2

Half of the speed of Car A before the collision

Explanation:

This problem can be solved by using conservation of momentum.

Since car B was stopped before the collision and its mass is twice the mass of A:

Also, since it is an elastic collision, car A stops after hitting car B. Rewriting the equation:

Therefore, the speed of car B after the collision is half of the speed of car A before the collision (v)

Vb = v/2

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6 cos 34, 6 sin 34 trig