Aphysicist is constructing a solenoid. she has a roll of insulated copper wire and a power supply. she winds a single layer of the wire on a tube with a diameter of dsolenoid = 10.0 cm. the resulting solenoid is ℓ = 60.0 cm long, and the wire has a diameter of dwire = 0.100 cm. assume the insulation is very thin, and adjacent turns of the wire are in contact. what power (in w) must be delivered to the solenoid if it is to produce a field of 6.40 mt at its center? (the resistivity of copper is 1.70 ✕ 10−8 ω · m.)

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

Lc=188.4 m

The magnetic filed given as

Now by putting the values

I=5.09 A

The resistance R given as

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

see earlier answer

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.