An electron moving at 2.97×103 m/s in a 1.25 t magnetic field experiences a magnetic force of 1.40×10−16 n . what angle (in degrees) does the velocity of the electron make with the magnetic field? there are two possible answers. [hint: most calculators will only return the answer that falls in the first quadrant (0 - 90 degrees), but there is another angle in the second quadrant (90 - 180 degrees) that also satisfies the equation.]

On a horizontal frictionless surface, a small block with mass 0.200 kg has a collision with a block of mass 0.400 kg. immediately after the collision, the 0.200 kg block is moving at 12.0 m/s in the direction 30° north of east and the 0.400 kg block is moving at 11.2 m/s in the direction 53.1° south of east. use coordinates where the +x-axis is east and the +y-axis is north.(a) what is the total kinetic energy of the two blocks after the collision (in ) what is the x-component of the total momentum of the two blocks after the collision? (indicate the direction with the sign of your ) what is the y-component of the total momentum of the two blocks after the collision? (indicate the direction with the sign of your answer.)