Atransformer has two sets of coils, the primary with n1 = 160 turns and the secondary with n2 = 1400 turns. the input rms voltage (over the primary coil) is δv1rms = 62 v. n1 = 160n2 = 1400δ v1rms = 62 v
1. express the output rms voltage, δv2 rms, in terms of n1, n2, and δv1 rms.2. calculate the numerical value of δv2rms in volts.

To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.

So things our data are given by

PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by

So the voltage for transformer 2 would be given by,

PART B) To express the number value we proceed to replace with the previously given values, that is to say

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

a 2,000 calorie based diet.