In a simple model of the wind speed associated with hurricane emily, we assume there is calm eye 7.5 km in radius. the winds, which extend to a height of 6900m, begin with a speed of 265.0 km/hr at the eye wall and decrease linearly with radial distance down to 0 km/hr at a distance of 57.5 km from the center. assume the average density of the air from sea level to an altitude of 6900 m is 0.830 kg/m3. calculate the total kinetic energy of the winds. note: to appreciate the hurricane's ke, compare your answer to the hiroshima atomic bomb which had an energy equivalent to about 15,000 tons of tnt, representing an energy of about 6.0×1013 j.

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  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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