A50kg i’ve skater goes around in a circle of radius 5.0m at a constant speed of 3.0m/s on a level ice rink. what is the magnitude of the horizontal force that the ice exerts on the skates?

90N

Explanation:

When resolving in a circular path we talk about Centripetal force

Mathematically;

Centripetal force (f) = mv^2 / r

Where m = mass

V = velocity

r = radius

Therefore;

50 x 3^2 / 5

= 90N

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.