Two blocks are arranged at the ends of a massless cord over a frictionless massless pulley as shown in the figure. assume the system starts from rest. when the masses have moved a distance of 0.355 m, their speed is 1.32 m/s. the acceleration of gravity is 9.8 m/s 2 . 4.1 kg 2.7 kg µ what is the coefficient of friction between m2 and the table?

The coefficient of friction is 0.242.

Explanation:

Given

Mass on the table is, kg

Hanging mass is, kg

Displacement of the masses is, m

Initial velocity of the masses is, m/s

Final velocity of the masses is, m/s

Acceleration by gravity is m/s².

The acceleration of the system is calculated using equation of motion and is given as:

Therefore, m/s²

Applying Newton's second law on the hanging mass, we get:

Now, applying Newton's second law on the mass on table, we get:

The normal force of the table on the mass is given as:

The coefficient of friction is the ratio of the frictional force and the normal force and is given as:

Therefore, the coefficient of friction between the mass on the table and the table is 0.242.

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neither accurate nor precise.