2. a scooter moves at a speed of 36km/h is stopped by applying brakes which produce a uniform acceleration of, -0.5m/s . how much distance will be covered by the scooter before it stops?

There will be covered 100 meter by the scooter before it stops.

Explanation:

Step 1: Data given

Velocity of the scooter = 36 km/h = 10 m/s = the initial velocity

Uniform acceleration = -0.5 m/s

Step 2:  Calculate time needed to stop the scooter

Suppose the scooter stops afer time t, then v= 0

v = v0+ a*t = 0    a = -0.5 m/s²

0 = 10 + (-0.5)*t

-10 = -0.5t

t= 20

This means the scooter will stop after 20 seconds

Step 3: Calculate distance travelled before the scooter stops

x = v0*t + 1/2at²

x = 10*20 + 1/2*(-0.5)*20²

x = 200 -100

x = 100 m

There will be covered 100 meter by the scooter before it stops.

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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