Abomber is flying horizontally at a speed of 800.0 ft/s and an altitude of 1000.0 ft when it is drops a bomb

 The range, S = 6307.82 ft

Explanation:

Given,

The horizontal velocity of the bomber, Vx = 800 ft/s

The altitude of the bomber, h = 1000 ft

The range of the projectile is given by the relation

                           S = Vx [Vy +√(Vy² + 2gh] / g

If the vertical component of the velocity is zero, the equation becomes

                           S = Vx √(2gh) / g    

Substituting the given values,

                            S = 800 √(2X 32.17 X 1000) /  32.17

                               = 6307.82 ft

Hence, the bomb falls at a distance, S = 6307.82 ft                  

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.