Arope is wrapped around the curved side of a cylinder .600 m in radius. a mass of 10.0 kg is suspended from the free end of the rope. if the cylinder is free to rotate about its long axis as the rope unwinds, what is the angular acceleration of the cylinder if its moment of inertia is 5.00 kgm2? ignore the mass of the rope.

If the cord does not slip

M=R*T=I*α ⇒T = I·α/R

T-m*g=-m*a ⇒ T=m*g-m*a

α=a/R

So ,

m*g-m*a = I*α/R = I*a/R²

⇒ I*a/R² + m*a= m*g

⇒ a=g/{1 + I/(m·R²)}

⇒ α=g/{R + I/(m·R)}

Where

M=Cilinder mass

I= Moment of inertia

a=acceleration

α=angular acceleration

m=mass suspended

R=radius

g=gravity

Considering g=9,81 m/sec²

α=10,75 {rad/sec²}

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

electrical power