Suppose we connect a 10-ohm light bulb to a 6-v battery. some current flows through the battery (calculate it). now, imagine that you add a 40-ohm resistor in parallel with the light bulb. by what factor does the current through the battery increase?

The current increases by the factor 1.25                  

Explanation:

We have given that a 6 volt battery is connected to light bulb

So voltage V = 6 volt

Resistance connected R = 10 ohm

In first case

From ohm's law we know that current is given by

In second case a 40 ohm resistor is connected in parallel

So equivalent resistance will be

R = 8 ohm

So the current will be

So the factor by which current increases

So the current increases by the factor 1.25  

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explanation:

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