Acat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 5.9 s. what is the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding?

0.53

Explanation:

Given

Radius of merry-go-round

Time Period

Velocity of merry-go-round

Now Friction Force will nullify the centripetal Force

i.e.

  , where coefficient of static friction

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.