An automobile with a radio antenna 1.0 m long generates an emf, v1, since it is traveling at 100.0 km/h in a location where the earth's horizontal magnetic field is 5.5x10-5t. at some time, the radio antenna doubles in length and the car begins traveling at a quarter of the original speed. what is the ratio of the new emf generated, v2, to the original emf. v1? 0.5v1 0.125 v1 111 0.75v1

option A

Explanation:

given,

length of antenna = 1 m

traveling at speed = 100 Km/h

Earth's horizontal magnetic field is 5.5 x 10⁻⁵ T

radio antenna doubles in length (l₂ = 2 l)

car begins traveling at a quarter of the original speed (v₂ = v/4)

ratio of new emf

we know, ε = B l v

V₁ = B₁ l₁ v₁...........(1)

V₂ = B₂ l₂ v₂...........(2)

dividing equation (2) from (1)

V₂ = 0.5 V₁

the correct answer is option A

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.