In an old house, the heating system uses radiators, which are hollow metal devices through which hot water or steam circulates. in one room the radiator has a dark color (emissitivity = 0.830). it has a temperature of 64.1 oc. the new owner of the house paints the radiator a lighter color (emissitivity = 0.426). assuming that it emits the same radiant power as it did before being painted, what is the temperature (in degrees celsius) of the newly painted radiator?

T = 125.30C

Explanation:

Using Stefan-Boltzmann law

P/A = e* Stefan-Boltzmann constant * T^4

Where p= radiant power in watts

e = emissivity

T = Temperature in kelvin

A= Surface area of the object measured in m^2

Considering that after painting the object have the radiant power then

0.83* A* Stefan-Boltzmann constant *(337.1^4) = 0.46 * A* Stefan-Boltzmann constant * Tnew^4

Cancelling the common terms yields

0.83*(337.1^4) = 0.426*Tnew^4

Fourthroot(0.83*(337.1^4)) = Tnew

Tnew = 398.3k = in degree Celsius 125.3

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

dopamine..

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