An electron is moving east in a uniform electric field of 1.47 {\rm n/c} directed to the west. at point a, the velocity of the electron is 4.55×105 {\rm m/s} pointed toward the east. what is the speed of the electron when it reaches point b, which is a distance of 0.355 {\rm m} east of point a?
a proton is moving in the uniform electric field of part a. at point a, the velocity of the proton is 1.95×104 {\rm m/s}, again pointed towards the east. what is the speed of the proton at point b?

a)

b)

Explanation:

Given data:

Electric field = 1.47 N/C

velocity of electron is

distance of point b from point A is 0.55 m

we know that acceleration of particle is given as

a) for electron

from equation of motion we have

b) for proton

from equation of motion we have

the inner core.

good luck: )

klicker

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.