The latent heat of fusion for water is 33.5 × 10⁴ j/kg, while the latent heat of vaporization is 22.6 × 10⁵ j/kg. what mass m of water at 0 °c must be frozen in order to release the amount of heat that 2.48 kg of steam at 100 °c releases when it condenses?

16.78kg

Explanation:

Data Given from question

Heat of fusion of water Lf=33.5×10^4 J/kg Lf=33.5×10^4 J/kg

Heat of vaporization Lv=22.6×10^5 J/kg Lv=22.6×10^5 J/kg

Mass of the steam condensed Ms=2.48 kgms=2.48 kg

From the condition given in the question

Heat Released during freezing = Heat released during condensation

Where Mw= Mass of water

MwLf=MsLv

MwLf=MsLv

Mw=MsLv÷Lf

Mw=MsLv÷Lf

Mw=2.48 kg×22.6×10^5 J/KG÷ 33.4×10^4 J/kg

Mw=2.48 kg×22.6×10^5 J/kg ÷33.4×10^4 J/kg

Therefore mass of water would be

Mw=16.78 kg

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