A1400 kg car is traveling on a level road at a constant speed of 26.8 m/s (60 miles per hour.) the drag force exerted by air on the car and the frictional force exerted by the road on the car’s tires add to give a net force of 680n pointing opposite to the direction of the car’s motion. what is the rate of work done (power) by the air and the road on the car

Power, P = 18224 watts

Explanation:

It is given that,

Mass of car, m = 1400 kg

Speed of the car, v = 26.8 m/s

The frictional force exerted by the road on the car’s tires, F = 680 N

We need to find the rate of doing work by the air and the road on the car. We know that rate of doing work is called power exerted. It is equal to the product of force and velocity. It is given by :

P = 18224 watts

So, the power delivered by the air and the road on the car is 18224 watts. Hence, this is the required solution.

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia