7. a mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110n @ an angle
of 30' with the horizontal. if the coefficient of friction between the wheels of the carriage and the grass is
0.14, calculate the weight, normal force, frictional force and the acceleration of the carriage.

Weight of the carriage

Normal force

Frictional force

Acceleration

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with , force of acting vertically downward.Both are downward and Normal is upward so Normal force

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that and component of forces.

So Fnet = Fy(Horizontal) - f(friction)

So we have the weight of the carriage, normal force,frictional force and acceleration.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

this could be newton#'s law of cooling. the cooling curve is exponential