A500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 n/m. the block rests on a frictionless surface. a 600 kg wad of putty is thrown horizontally at the block, hitting it with a speed of 4.4 m/s and sticking. how far does the putty-block system compress the spring?

x = 0.396 m

Explanation:

The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is   spring

Data the putty has a mass m1 and velocity vo1, the block has a mass m2 .  t's start using the moment to find the system speed.

Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash

    p₀ = m1 v₀₁

Moment after shock

    = (m1 + m2)

   p₀ =

   m1 v₀₁ = (m1 + m2)

  = v₀₁ m1 / (m1 + m2)

   = 4.4 600 / (600 + 500)

  = 2.4 m / s

With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring

Before compressing the spring

   Em₀ = K = ½ (m1 + m2) ²

After compressing the spring

    = Ke = ½ k x²

As there is no rubbing the energy is conserved

   Em₀ =

   ½ (m1 + m2) ² = = ½ k x²

   x = √ (k / (m1 + m2))

   x = 2.4 √ (11/3000)

   x = 0.396 m

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explanation:

it's just that the ecronimia of the shell is supercharged with electro bolts

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.