Aconducting rod of length l = 28.5 cm slides over two horizontal metal bars with a constant speed v to the right through a distance δx in a time δt. the entire set up is in a region of uniform magnetic field of magnitude 1.60 t that is directed perpendicular to the rods and out of the page. if the induced emf has a magnitude of 1.00 v, what is the speed with which the rod moves? what is the direction of the induced current in the resistor r?

v =  2.19 m/s  Anti-clockwise

Explanation:

Given data:

L = 28.5 cm

magnetic field = 1.60 T

Induced emf 1.00 V

Induced emf

Where A is area

area at any point  A = Lx

v =  2.19 m/s

b) Induced emf & induced current are such that they oppose the change is flux.

As the area decreases with rod shift to left, hence the flux decreases. And induced emf will generate induced current in a such a way that induced magnetic field will be in direction of initial magnetic field. Therefore Anti-clockwise

i wanna say it’s between b and d, leaning more towards b.