Atruck is traveling at 11.9 m/s down a hill when the brakes on all four wheels lock. the hill makes an angle of 15 ° with respect to the horizontal. the coefficient of kinetic friction between the tires and the road is 0.861. how far does the truck skid before coming to a stop?

s = 12.62 m

Explanation:

given,

speed of the truck = 11.9 m/s

angle of inclination =15 °

coefficient of friction = 0.861

we know,

we know

m a  =μ m g cos θ - m g sinθ

a = μ g cos θ - m sinθ

a = 0.861 x 9.8 x cos 15 ° - 9.8  sin15°

a = 5.61 m/s²

we know

v² = u² + 2 a s

final velocity zero

0² = u² - 2 a s

11.9² = 2 x 5.61 x s

s = 12.62 m

explanation:

newton's third law, for every action there is an equal and opposite reaction.

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )