Asample is subjected to uv-vis spectroscopy in a 1 cm cell, and 23.2% of the incident light is transmitted through the sample to the detector. if the molar absorptivity of the analyte in the sample is 450 l/(mol*cm), what is the concentration of the analyte in the sample?

0.001410 mol/L is the concentration of the analyte in the sample.

Explanation:

Using Beer-Lambert's law :

Formula used :

where,

A = absorbance of solution

C = concentration of solution =

l = path length = 1.00 cm

= incident light

= transmitted light

= molar absorptivity coefficient

Here we are given :

Transmittance of light = T = 23.2%

C = 0.001410 mol/L

0.001410 mol/L is the concentration of the analyte in the sample.

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