Car a is driving east toward an intersection. car b has already gone through the same intersection and is heading north. at what rate is the distance between the cars changing at the instant when car a is 40 miles from the intersection and traveling at 50 mph and car b is 30 miles from the intersection and traveling at 60 mph? are the cars getting closer together or farther apart at this time?

76 mi/h

Explanation:

= Velocity of car A = 50 mi/h

a = Distance car A travels = 40 mi

= Velocity of car B = 60 mi/h

b = Distance car B = 30 mi

c = Distance between A and B after 3 hours = √(a²+b²) = √(40²+90²) = 50 mi

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

∴ Rate at which distance between the cars is increasing is 76 mi/h

The cars are getting farther apart at this time

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.