Before colliding the momentum of block a is +15.0 kg*m/s, and block b is -35.0 kg*m/s. after, block a has a momentum -12.0 kg*m/s. what is the momentum of block b afterwards? (unit=kg*m/s) remember: right is +, left is - me

The momentum of block B = -8 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The initial momentum of block B, mu = -35 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

The final momentum of block B, mv = ?

Consider the block B is initially at rest.

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                               MU + mu = MV + mv

                               15  +  (-35) = (-12) + mv

                                       mv = -20 + 12

                                             =  -8 Kg m/s

Hence, the momentum of the block B after impact is, mv = -8 Kg m/s

the answer would be c

the answer would be   dignified - apex