Physics, 10.11.2019 21:31, tonimgreen17p6vqjq

You and your brother are pushing a car with dead battery with forces of 20n and 25 n in the same direction what is the net force applied on the car

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answered: juana18

The net force, F = 45 N

Explanation:

Given,

I applied a force on the car, F₁ = 20 N

My brother applied a force on the car, F₂ = 25 N

Neglecting the frictional force of the car

The two forces act in the same direction, so the magnitude of the resultant force is equal to the algebraic sum of the individual forces. The direction of the resultant force is along the line of the original force.

The net force is given by the formula,

F = F₁ + F₂

Substituting the given values in the above equation,

F = 20 N + 25 N

= 45 N

Hence, the resultant force applied to the car is, F = 45 N

answered: Guest

Your answer is c. explanation: plasma is the fourth state of matter, derived from the gaseous state of matter. plasma can contain free electrons and/or ions. while plasma is never neutral, it can either be positively or negatively charged. gases, however, are electrically neutral.

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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You and your brother are pushing a car with dead battery with forces of 20n and 25 n in the same dir...