Two constant forces act on an object of mass m = 5.60 kg object moving in the xy plane as shown in the figure below. force f1 is 27.5 n at 35.0°, and force f2 is 41.0 n at 150°. at time t = 0, the object is at the origin and has velocity (4.70i + 2.55j) m/s 150° 35.0 (a) express the two forces in unit-vector notation (b) find the total force exerted on the object. (c) find the object's acceleration m/s now, consider the instant t = 3.00 s (d) find the object's velocity m/s (e) find its position (f) find its kinetic energy from ½mvf2 (g) find its kinetic energy from ½mvi2 σf·

Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Part g)

Explanation:

Part a)

first force is given as

at 35 degree

Second force is given as

at 150 degree

Part b)

Total force is given as

Part c)

as we know

F = ma so object acceleration is given as

Part d)

By kinematics we know that

Part e)

As we know that final position is given as

Part f)

final kinetic energy is given as

Part g)

final kinetic energy is given as

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explanation:

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