Apoint charge q is surrounded by a spherical surface of radius r0, whose center is at c. later, the charge is moved to the right a distance r0/2, but the sphere remains where it was. how is the electric flux through the sphere changed? is the electric field at the surface of the sphere changed? for each "yes" answer, describe the change.

Explanation:

We shall apply Gauss's law to find the result which states that total normal electric flux over a closed surface equals the 1 /ε₀ times the charge enclosed within the closed surface .

In the given case , a charge enclosed within a  sphere is placed at the centre . It is shifted to another point within the sphere . This change in its position within the sphere will not alter the magnitude of total flux over the surface due to charge according to Gauss's law because this law does not specify  the position of charge within the closed surface. The only condition is that it must lie within the closed surface.

But the electric field at a point changes when we change the position of a charge near  it. The electric field depends upon the distance of point from the charge where the field is measured .

In the given case, point on the surface which is near to the charge will have greater field and  points on the surface  far away will have less intense field

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