Agas is compressed from an initial volume of 5.40 l to a final volume of 1.20 l by an external pressure of 1.00 atm. during the compression the gas releases 128 j of heat. part a what is the change in internal energy of the gas?

296.2J

Explanation:

From the first law, you should know that the change in internal energy of a system is given by:

ΔE = q + w

where q is the heat added to the system (q is negative if heat is released from the system)

and w is the work done on the system by the surroundings.

We are told that q = -128 J.

Because the volume of the system decreases, the surroundings are doing work on the system, so w will be positive. If the compression is done "quasistatically", so that the internal pressure of the system is always infinitesimally close to the external pressure, then the work done is w = p*ΔV

1 atm = 1.01*10^5 Pa, and 1 liter = 10^-3 m^3, so:

w = (1.01^10^5 N/m^2)*(5.40 - 1.20)*10^-3 m^3

w = 424.2 J

The change internal energy is then:

ΔE = -128 J + 424.2J = + 296.2 J

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..

i think the answer is a, hope this : )