Two parallel-plate capacitors have the same plate area. capacitor 1 has a plate separation twice that of capacitor 2, and the quantity of charge you place on capacitor 1 is four times the quantity you place on capacitor 2. part a how do the potential differences across each of the two capacitors compare to each other?

Explanation:

Given that:

We know that the Capacitance of a parallel plate capacitor is directly proportional to the area and inversely proportional to the distance of separation.

Mathematically given as:

.....................................(1)

where:

k = relative permittivity of the dielectric material between the plates= 1 for air

From eq. (1)

For capacitor 2:

For capacitor 1:

We know, potential differences across a capacitor is given by:

..........................................(2)

where, Q = charge on the capacitor plates.

for capacitor 2:

& for capacitor 1:

hypothesising or postulating

wavelength divides in half and speed stays the same.