An elevator and its load have a combined mass of 1200 kg. find the tension in the supporting cable when the elevator, originally moving downward at 10 m/s, is brought to rest with constant acceleration in a distance of 62 m. (hint: if the elevator is slowing down and moving down then the upward force is greater)

12739.74 N

Explanation:

m = Mass of load + Mass of elevator = 1200 kg

s = Displacement of the elevator = 62 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 10 m/s

v = Final velocity = 0

Equation of motion

Tension on the cable

Here, as the elevator is going down the acceleration due to gravity and the acceleration will be subtracted.

Hence,  the tension in the supporting cable is 12739.74 N

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong